Hi all,
I use this command to see disk usage:
du -cks * | sort -rn | while read size fname; do for unit in k M G T P
E Z Y; do if [ $size -lt 1024 ]; then echo -e
"${size}${unit} ${fname}"; break; fi; size=$((size/1024)); done; done
The data itself is around 200GB with lots of subdir and small files.
The command takes for about 1 hour to finish.
Is there a faster way to see the disk usage of some directories?
Secondary objective is:
To see which directories have changes (added/remove subdir/files)
comparing to the previous data. I'm thinking of using "ls -laR" and
"diff". But not sure.
Thank you.
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02-15-2011, 09:58 AM
John Doe
Most efficient/fastest way to see disk usage
From: Fajar Priyanto <fajarpri@arinet.org>
> To see which directories have changes (added/remove subdir/files)
> comparing to the previous data. I'm thinking of using "ls -laR" and
> "diff". But not sure.
Maybe something like:
find / -exec stat -c "%i %a %u %g %s %Y %Z %n" '{}' ; > before
then rerun after and diff...?
JD
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